(x+6)(x-6)-(x-5)^2=40-17(x-2)

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Solution for (x+6)(x-6)-(x-5)^2=40-17(x-2) equation: 



(x+6)(x-6)-(x-5)^2=40-17(x-2)

We move all terms to the left:

(x+6)(x-6)-(x-5)^2-(40-17(x-2))=0

We use the square of the difference formula

x^2-(x-5)^2-(40-17(x-2))-36=0



We calculate terms in parentheses: -(40-17(x-2)), so:

40-17(x-2)

determiningTheFunctionDomain
-17(x-2)+40

We multiply parentheses

-17x+34+40

We add all the numbers together, and all the variables

-17x+74

Back to the equation:

-(-17x+74)



We get rid of parentheses

x^2-(x-5)^2+17x-74-36=0

We add all the numbers together, and all the variables

x^2+17x-(x-5)^2-110=0

We move all terms containing x to the left, all other terms to the right

x^2+17x-(x-5)^2=110

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